Home Physics Newton's Laws of Motion JEE Main 2023 A small block of mass 100 g is tied to a spr…
Physics Newton's Laws of Motion JEE Main 2023 MCQ (Single Correct)

A small block of mass 100 g is tied to a spring of spring constant 7. 5 N m -1 and length 20 cm. The other end of spring is fixed at a particular point A. If the block moves in a circular path on a smooth horizontal surface with constant angular velocity 5 rad s -1 about point A, then tension in the spring is

A
0.75N
B
0.25N
C
0.50 N
D
1.5N

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
A

Centripetal force will be provided by the spring force. Let the elongation in the spring be x, then we can write

Therefore, required tension will be T = kx = 0. 75 N.

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.